49+x^2=2x^2+2x+2

Solution for 49+x^2=2x^2+2x+2 equation:

49+x^2=2x^2+2x+2

We move all terms to the left:

49+x^2-(2x^2+2x+2)=0

We get rid of parentheses

x^2-2x^2-2x-2+49=0

We add all the numbers together, and all the variables

-1x^2-2x+47=0

a = -1; b = -2; c = +47;
Δ = b2-4ac
Δ = -22-4·(-1)·47
Δ = 192
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{192}=\sqrt{64*3}=\sqrt{64}*\sqrt{3}=8\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-8\sqrt{3}}{2*-1}=\frac{2-8\sqrt{3}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+8\sqrt{3}}{2*-1}=\frac{2+8\sqrt{3}}{-2}
$